Question

find the zero of the polynomial x2-36

Answer 1

⭐Hey here is your answer...⭐


x^2 - 36 = 0

(x)^2 - (6)2


(x + 6)(x - 6) = 0

either ,
x +6 = 0

x = -6

or ,

x -6 = 0

x = 6



I HOPE IT WILL HELP YOu ☺️☺️


Thnx for asking ur question ✌️✌️

Answer 2

Hi...☺

Here is your answer...✌

To find zeros of polynomial ,We put

x² - 36 = 0

x² - 6² = 0

(x + 6) (x - 6) = 0

[ Using Identity a² - b² = (a+b) (a-b) ]

=> x + 6 = 0 or x - 6 = 0

=> x = -6 or x = 6

Hence,

Zero of polynomial x² - 36 are -6 and 6