Question

Find the zero of the polynomial : y^2+2y -3

Answer 1

y^2 + 2y - 3
=> y^2 + ( 3 - 1 ) y - 3
=> y^2 + 3y - y - 3
=> y ( y + 3 ) -1 ( y + 3)
=> ( y - 1 ) ( y + 3)
Putting y = 0
We get y = 1 and -3
So the zeroes are 1 and -3

Answer 2

$Hey$‼

$y^2+2y-3=0$

$y^2+3y-y-3=0$

$y(y+3)-(y+3)=0$

$(y-1)(y+3)=0$

$(y-1)=0\:or\:(y+3)=0$

$y=1\:or\:y=-3$