Find the zero of the quadratic polynomial 4 and verify its relationship between the zeroes and the coefficients.
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Answer:
Let f(x)=4x
2
−4x−3
By splitting the middle term, we get f(x)=4x
2
−6x+2x−3
=2x(2x−3)+1(2x−3)
=(2x+1)(2x−3)
On putting f(x)=0, we get (2x+1)(2x−3)=0
⇒2x+1=0 or 2x−3=0
⇒x=
2
−1
Or x=
2
3
Thus, the zeroes of the given polynomial 4x
2
−4x−3 are
2
−1
and
2
3
Verification:
Sum of zeroes =α+β=
2
−1
+
2
3
=
2
−1+3
=1
=−
Coefficient of x
2
Coefficient of x
=−
4
(−4)
=1
Product of zeroes =αβ=
2
−1
×
2
3
=
4
−3
=
Coefficient of x
2
Constant term
=
4
−3
So, the relationship between the zeroes and the coefficients is verified.
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