Question

find the zero of the quadratic polynomial t^2–15

Answer 1

heya Mate here is your answer goes :

t² - 15

using identity a² - b² = (a+b) (a-b)

= (t)² - (√15)²

= (t - √15) (t + √15)

= t = √15 and t = -√15

hope it helps you

Answer 2

Answer:

$\\ \tt \: {t}^{2} - 15 = {t}^{2} - \sqrt{( 12) } {}^{2} \\ \\ \\ \tt \: (t - \sqrt{15} ) \: (t + \sqrt{15} )$

So, zeroes are √15 and -√15 ,

$\\ \tt \: t = \sqrt{15} = 0 \\ \\ \tt \implies \: t = \sqrt{15}$

or,

$\tt \ \: t + \sqrt{15} = 0 \\ \\ \implies \tt \: t = - \sqrt{15}$