Question

find the zero of thr polynomial p(x)=2x^2-9

Answer 1

Step-by-step explanation:

2x² - 9

By using quadratic formula,

D = b² - 4ac

D = 0² - 4(2)(-9)

D = 72

$x = \frac{ {b}^{2} + - \sqrt{d} }{2a}$

$x = \frac{{0}^{2} + - \sqrt{72} }{4}$

The zeros of the polynomial is

$x = \frac{ \sqrt{72} }{4} or \: \frac{ - \sqrt{ 72} }{4}$

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Answer 2

Answer:

2x² - 9

By using quadratic formula,

D = b² - 4ac

D = 0² - 4(2)(-9)

D = 72

The zeros of the polynomial is

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