Question

find the zero of x square -9
$find \: the \: zero \: of \: x{2} - 9$

Answer 1

Here's the answer:


To find zero of x²-9:
say p(x)= x²-9
equate p(x) to 0
x²-9= 0
x²= 9
x=√9
x= 3

•°•zero of x²-9= 3

;)
hope it helps

Answer 2

$hi \: ....$
$here's \: your \: answer \:$

We have to find the zeroes of :
${x}^{2} - 9$
So.....

${x}^{2} - 9 = 0$
${x}^{2} = 0 + 9$
${x}^{2} = 9$
$x = \sqrt{9}$
$x = + 3 \: \: or \: \: - 3$

Hence , the zeroes of
${x}^{2} - 9 \:$
are : 3 & -3
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$hope \: \: this \: \: helps..$