Question

find
the
Zero
polynomial x²+6x+8x
and verify the
relacionship between zeroes and the
Coefficient​

Answer 1

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Answer 2

Answer:

$x {}^{2} + 6x + 8 = 0 \\ x { }^{2} + 4x + 2x + 8 = 0 \\ x(x + 4) + 2(x + 4) = 0 \\ (x + 4)(x + 2) = 0 \\ x = - 2 = \alpha \\ x = - 4 = \beta \\ \alpha + \beta = - 2 - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{ - b}{a} = \frac{ - 6}{1} \\ = - 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 6 \\ therefore \: \: \alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = - 2 \times - 4 \: \: \: \: \: \: \: \frac{c}{a} = \frac{8}{1} \\ = 8 \: \: \: \: \: \: \: \: \: \: \: = 8 \\ therefore \: \: \: \alpha \beta = \frac{c}{a}$

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