Math, asked by AlenPaul, 7 months ago

Find the Zero's of - 3x^2 -x -4​

Answers

Answered by Anonymous
7

Answer:

3x²-x-4=0

3x²+ 3x - 4x -4 = 0

3x(x + 1) - 4(x + 1)=0

3x - 4= 0 x + 1= 0

3x= 4 x = -1

x = 4/3

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Answered by shashu2004
2

Answer:

Step-by-step explanation:

=3x^2-x-4

=3x^2-4x+3x-4

=x(3x-4)+1(3x-4)

=(x+1)(3x-4)

Zeroes are -1 and 4/3

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