Find the Zero's of - 3x^2 -x -4
Answers
Answered by
7
Answer:
3x²-x-4=0
3x²+ 3x - 4x -4 = 0
3x(x + 1) - 4(x + 1)=0
3x - 4= 0 x + 1= 0
3x= 4 x = -1
x = 4/3
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Answered by
2
Answer:
Step-by-step explanation:
=3x^2-x-4
=3x^2-4x+3x-4
=x(3x-4)+1(3x-4)
=(x+1)(3x-4)
Zeroes are -1 and 4/3
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