Question

Find the zero's of polynomial p(x) equal to x square - 10x + 21 and verify the relationship between the zero's and the coefficients step by step process​

Answer 1

Step-by-step explanation:

x^2+10x+21

= x^2+7x+3x+21

= x(x+7)+3(x+7)

=(x+3)(x+7)

therefore, zeros are -2,-7

sum of zeroes = {-3+(-7)}= -10

-b/a=-10/1 = -10

sum of zero varified

product of zeroes = -3×-7 =21

c/a= 21/1=21