Question

find the zero's of the quadratic polynomial x2.-2x-8​

Answer 1

Answer:

${x}^{2} - 2x - 8 \\ {x }^{2} - 4x + 2x - 8 \\ x(x - 4) + 2(x - 4) \\ x - 4 = 0 \: \: \: \: x + 2 = 0 \\ x = 4 \: \: \: \: \: x = - 2$

zeroes are 4,-2

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Answer 2

Answer:

answer is +7&-5

Explanation:

by using quadratic formula we can get this numbers