Question

find the zeroes 2x_8x+6​

Answer 1

Answer:

2x^2-8x+6

=2x^2-2x-6x+6

2x(x-1) -6(x-1)

(x-1) = 0 or (2x-6) = 0

x=1 or x=3

therefore the zeroes are 1 and 3

Answer 2

$= 2 {x}^{2} - 8x + 6$

$= 2 {x}^{2} - (6 + 2)x + 6$

$= 2 {x}^{2} - 6x - 2x + 6$

$= 2x(x - 3) - 2(x - 3)$

$= (2x - 2)(x - 3)$