find the zeroes 2xsq - 11x +15
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Answered by
2
for the zeros of the equation let 2x^2-11x+15=0
by splitting the middle term 2x^2-6x-5x+15=0
2x(x-3)-5(x-3)=0
(x-3)(2x-5)
x=3 ,5/2
hope this will help you dear
by splitting the middle term 2x^2-6x-5x+15=0
2x(x-3)-5(x-3)=0
(x-3)(2x-5)
x=3 ,5/2
hope this will help you dear
Answered by
1
= 2 x^2 - 11 x + 15
To factorize any quadratic polynomial middle term has to be split in such a way that its product should be equal to product of first term and third term and sum should be equal to middle term.
= 2 x^2 - 6 x - 5 x + 15
= 2 x ( x - 3 ) - 5 ( x - 3 )
= ( x - 3 ) ( 2 x - 5 ) = 0
( x - 3 ) = 0 or ( 2 x - 5 ) = 0
x = 3 or 2 x = 5
or x = 5 / 2.
Zeroes of 2x^2 - 11 x + 15 are 3 and 5/2.
To factorize any quadratic polynomial middle term has to be split in such a way that its product should be equal to product of first term and third term and sum should be equal to middle term.
= 2 x^2 - 6 x - 5 x + 15
= 2 x ( x - 3 ) - 5 ( x - 3 )
= ( x - 3 ) ( 2 x - 5 ) = 0
( x - 3 ) = 0 or ( 2 x - 5 ) = 0
x = 3 or 2 x = 5
or x = 5 / 2.
Zeroes of 2x^2 - 11 x + 15 are 3 and 5/2.
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