Question

find the zeroes of
1
$3 {x}^{2} - \sqrt{3} x - 2$
2
$4 {x}^{2} + 5 \sqrt{2} x - 3$
please answer fast...​

Answer 1

✍️${\huge{\red{\boxed{\purple{\underline{\mathfrak{ANSWER}}}}}}}\\</p><p>1) \: 3 {x}^{2} - \sqrt{3} x - 2 = 0 \\ 3 {x}^{2} + \sqrt{3} x - 2 \sqrt{3} x - 2 = 0 \\ \sqrt{3} x( \sqrt{3} x + 1) - 2 ( \sqrt{3} x + 1) = 0 \\ ( \sqrt{3}x+ 1)( \sqrt{3}x - 2) = 0 \\ x = \frac{( - 1)}{ \sqrt{3} } \: and \: x = \frac{2}{ \sqrt{3} } \\ 2) \: 4 {x}^{2} + 5 \sqrt{2} x - 3 = 0 \\ 4 {x}^{2} + 6 \sqrt{2}x - \sqrt{2} x - 3 = 0 \\ 2 \sqrt{2} x( \sqrt{2} x + 3) - 1( \sqrt{2} + 3) = 0 \\ ( \sqrt{2} x + 3)(2 \sqrt{2} x - 1) = 0 \\ x = \frac{( - 3)}{ \sqrt{2} } \: and \: x = \frac{1}{2 \sqrt{2} }$✍️

1) x=(-1)/√3 , 2/√3 are the zeros of the equation.

2) x=(-3)/√2 , 1/2√2 are the zeros of the equation.