Question

find the zeroes of 100x2-81and verify the relationship between the zeroes and there coefficient​

Answer 1

Step-by-step explanation:

HERE,P(x)=100x²-81

NOW,LET P(x)=0

•°•100x²-81=0

•°•100x²=81

•°•x²=81/100

•°•x=±9/10

SO,LET ALPHA=9/10 AND

BETA. = -9/10

NOW,SUM OF ZEORES =9/10 - 9/10

=0

= -(-0)/100

= -b/a

NOW,PRODUCT OF ZEORES=9/10×(-9/10)

= -81/100

=c/a