Math, asked by khushboo4887, 7 months ago

find the zeroes of ......​

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Answered by Saikrisnarao
1

\huge{\mathrm{\bigstar{\fbox {\fbox {\red{Answer:-}}}}}}{\bigstar}

 \sqrt{3 }{x}^{2} + 10 x + 7 \sqrt{3 }  \\ \sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3}   \\ \sqrt{3}x (x +  \sqrt{3} ) + 7(x +  \sqrt{3} ) \\  (\sqrt{3}  {x}+ 7)(x +  \sqrt{3  } )  = 0\\  \sqrt{3} x + 7 = 0 \: (or) \: x +   \sqrt{3}  = 0 \\  \sqrt{3} x =  - 7 \: (or )\: x =  -  \sqrt{3}  \\ x =  \frac{ - 7}{ \sqrt{3} }  \: (or )\: x =  -  \sqrt{3}  \: is \: the \: answer

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