Question

Find the zeroes of 2x3 – 11x2 + 17x – 6

Answer 1

Answer:

Factorise 2x³-11x²+17x-6

Use x-2 so value of x become 2

Put value of x in the equation you find remainder =0

then divide Equation by x-2

then u get

(x-2) (2x²-7x+3)

then u factorise 2x²-7x+3

2x²-6x-x+3

you get

(x-2)(2x-1)(x-3)

After that u find αβ¥

by putting =0 in (x-2)=0

2x-1=0

x-3=0

u get

x=2,x=1/2,x=3 these are values of zeroes αβ¥

Answer 2

Answer:

Step-by-step explanation: