find the zeroes of 2y2-7y-5 and verify the relations between the zeroes and the co-efficient
Answers
Given:
A quadratic equation 2y2-7y-5
To find:
Find the zeroes of 2y2-7y-5 and verify the relations between the zeroes and the co-efficient
Solution:
From given, we have,
A quadratic 2y2-7y-5
equate the quadratic equation to zero to find the zeros.
2y2 - 7y - 5 = 0
x = -b±√[b² - 4ac]/2a
x = -7±√[(-7)² - 4 × 2 × -5]/2(2)
x = -7±√(89)/4
sum of zeros = -b/a = - (-7)/2 = 7/2
-7+√(89)/4 + [-7-√(89)/4] = 14/4 = 7/2
product of zeros = c/a = -5/2
-7+√(89)/4 × [-7-√(89)/4] = - 5/2
Therefore, the relations between the zeroes and the co-efficient is satisfied.
Answer:
Given:
A quadratic equation 2y2-7y-5
To find:
Find the zeroes of 2y2-7y-5 and verify the relations between the zeroes and the co-efficient
Solution:
From given, we have,
A quadratic 2y2-7y-5
equate the quadratic equation to zero to find the zeros.
2y2 - 7y - 5 = 0
x = -b±√[b² - 4ac]/2a
x = -7±√[(-7)² - 4 × 2 × -5]/2(2)
x = -7±√(89)/4
sum of zeros = -b/a = - (-7)/2 = 7/2
-7+√(89)/4 + [-7-√(89)/4] = 14/4 = 7/2
product of zeros = c/a = -5/2
-7+√(89)/4 × [-7-√(89)/4] = - 5/2
Therefore, the relations between the zeroes and the co-efficient is satisfied.
Step-by-step explanation: