Question

Find the zeroes of √3 x² + 10x + 7√3 .

Answer 1

Answer:

x=-√3or-7/√3

Step-by-step explanation:

√3x^2+10x+7√3

(√3x^2+7x)+(3x+7√3)

x(√3x+7)+√3(√3x+7)

(x+√3) (√3x+7)

x=-√3 or x=-7/√3

Answer 2

Answer:

$= \sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} \\ = \sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3} \\ = \sqrt{3}x(x +\sqrt{3}) + 7(x + \sqrt{3}) \\ = (x + \sqrt{3})( \sqrt{3}x + 7) \\ x = - \sqrt{3} \: \: or \: \: x = - 7 \div \sqrt{3} .$