Find the zeroes of √3x square+10x+7√3
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Hola there,
=> √3x² + 10x + 7√3
=> √3x² + 3x + 7x + 7√3
=> √3x(x + √3) + 7(x + √3)
=> (x + √3)(√3x + 7)
=> x = -√3 and -7/√3
Hope this helps...:)
=> √3x² + 10x + 7√3
=> √3x² + 3x + 7x + 7√3
=> √3x(x + √3) + 7(x + √3)
=> (x + √3)(√3x + 7)
=> x = -√3 and -7/√3
Hope this helps...:)
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Hope it helps
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