Find the zeroes of 4x²-3 and relationship between them
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Answer:
Zeroes are root 3/2 and -root 3/2
Step-by-step explanation:
4x^2-3
=(2x-root3) (2x+root3)
alpha=root3/2
beta=-root3/2
relation root3/2 + (-root3/2)=0=-b/a
( root3/2) (-root3/2)=-3/4=c/a
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