Question

Find the zeroes of 6√6x^2 + x - 4√3

Answer 1

Answer:

±$\sqrt{288\sqrt{2}+1 }$-1/$12\sqrt{6}$

Step-by-step explanation:

Using Quadratic Formula,

-b±$\sqrt{b^{2}-4ac }$/2a

== ±$\sqrt{288\sqrt{2}+1 }$-1/$12\sqrt{6}$