Question

find the zeroes of 6x square-3-7x and verify the relationship between zeores and coefficients​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

We are given the polynomial -

$6x^2 - 3 - 7x$

First, we need to arrange the polynomials in the following sequence :-

ax² + bx + c.

So, it can be written as, after rearranging it :-

$6x^2 - 7x - 3$

Now, we can get the other values.

We will use middle term factorization:-

6x² - 9x + 2x - 3

=> 3x(2x - 3) + 1(2x-3)

(3x+1)(2x-3)

Now, we have the zeroes as -1/3 and 3/2 , after equating them to zero.

Refer to Attachment now.