find the zeroes of a polynomial x3-15x2+71x-105 given that the zeroes are in ap
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Let zeroes are and,a,a+d
Sum of roots=3a
3a=15
a=5
(a-d)a+a(a+d)+(a-d)(a+d)=71
d^2=4
d=2
So,zeroes are 3,5,7
Sum of roots=3a
3a=15
a=5
(a-d)a+a(a+d)+(a-d)(a+d)=71
d^2=4
d=2
So,zeroes are 3,5,7
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