Question

find the zeroes of cubic polynomial of i)-x³ ii) x²-x³ iii) x³-5x²+6x ​

Answer 1

Answer:

0

Step-by-step explanation:

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Answer 2

i) -x³
here one zeros x=0

ii) x²-x³
= x²(1-x)
here two zeros x=0,1

iii) x³-5x²+6x
=x(x²-5x+6)
=x(x²-2x-3x+6)
=x[x(x-2)-3(x-2)]
=x(x-2)(x-3)

here three zeros x=0,2,3