find the zeroes of each of the following polynomials and verify the relation between zeroes and its coefficient 6xsquare-3
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Hola there,
=> 6x² - 3 = 0
=> 3(2x² - 1) = 0
=> 2x² - 1 = 0
=> x² = 1/2
=> x = ±√1/2
Zeroes of polynomial are +√1/2 and -√1/2
Verification.
a = 6
b = 0
c = -3
Alpha + beta = +√1/2 - √1/2
= 0
= -b/a
= 0/6
= cofficient of x/cofficient of x²
Alpha×beta = +√1/2×(-√1/2)
= -1/2
= c/a
= -3/6
= -1/2
= constant term/cofficient of x²
Hope this helps...:)
=> 6x² - 3 = 0
=> 3(2x² - 1) = 0
=> 2x² - 1 = 0
=> x² = 1/2
=> x = ±√1/2
Zeroes of polynomial are +√1/2 and -√1/2
Verification.
a = 6
b = 0
c = -3
Alpha + beta = +√1/2 - √1/2
= 0
= -b/a
= 0/6
= cofficient of x/cofficient of x²
Alpha×beta = +√1/2×(-√1/2)
= -1/2
= c/a
= -3/6
= -1/2
= constant term/cofficient of x²
Hope this helps...:)
Anonymous:
give the link of the question..
I will try
root 3xsquare +10x+7root3
done!!
yes
alpha upon bita plus bita upon alpha
please solve it
done!!
one upon alpha plus one upon beta
you are girl or boy
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