find the zeroes of following polynomials. Зx^2 + 8x + Ч
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Answered by
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Step-by-step explanation:
3x²+8x+4
factors of 4 = ±1, ±2
p(x)=3x²+8x+4
x=-2
p(-2)= 3(-2)²+8(-2)+4
p(-2)=12-16+4
p(-2)=-4+4
p(-2)=0
Hope it helped
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