FIND THE ZEROES OF P(x) = 4X SQUARE +4X+1
no spam plz
Answers
Answered by
5
Ahoy user!
The answer!
p(x) = 4x^2+4x+1
=> 4x^2 + (2x+2x) +1
=>( 4x^2 +2x) +( 2x + 1)
=> 2x(2x+1) +1 (2x+1)
=>(2x+1)(2x+1)
Therefore zeroes are:-
>2x+1=0
2x=-1
x= -1/2
>2x+1=0
2x=-1
x=-1/2
So,
The two zeroes are
-1/2 & -1/2
hope this helps!
Good day!
The answer!
p(x) = 4x^2+4x+1
=> 4x^2 + (2x+2x) +1
=>( 4x^2 +2x) +( 2x + 1)
=> 2x(2x+1) +1 (2x+1)
=>(2x+1)(2x+1)
Therefore zeroes are:-
>2x+1=0
2x=-1
x= -1/2
>2x+1=0
2x=-1
x=-1/2
So,
The two zeroes are
-1/2 & -1/2
hope this helps!
Good day!
Anonymous:
tysm fr brainliest!!
what is np
o ya
Similar questions