Question

Find the zeroes of p(x)=x^2+2√2x-6 by factorisation

Answer 1

x^2+3√2x-√2x-6
x(x+3√2)-√2(x+3√2)
(x-√2)(x+3√2)
The zeroes are √2 and -3√2 ok now Mark it

Answer 2

to factorise we first find the multiplication of coefficient of x*2 and constant term and then try to express coefficient of x in the form of a addition of the factors of the number got after mutiplication

x^2+2root2-6
multiplication of the terms=-6
expressing as the sum of factors =3root2-root2
x^2+3root2x-root2x-6
taking x common in first two terms and
-root2 common in the last two terms
x (x+3root2)-root2 (x+3root2)
taking (x+3root2)common
(x+3root2)(x-root2)

for finding roots of x put it equal to 0

(x+3root2)(x-root2)=0

now two cases arise
case-1
(x+3root2)=0
x=-3root2
case-2
(x-root2)=0
x=root2


hope it helps ...............
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