Question

find the zeroes of polynomial 3x^2+4x+1

Answer 1

hey here is ur answer
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3x²+4x+1=0
3x²+(3+1)x+1=0
3x²+3x+x+1=0
3x(x+1)+1(x+1)=0
(3x+1)(x+1)=0
if 3x+1=0
x=-1/3

or if x+1=0
x=-1

so the zeros of polynomial is -1/3, -1

Answer 2

3x^2+4x+1=0
3x^2+3x+x+1=0
3x(x+1)+1(x+1)=0
(x+1)(3x+1)=0
x=-1 or x=-1/3