Question

find the zeroes of polynomial 6x²-3-7x​

Answer 1

Answer:

$\large\boxed{\sf{\dfrac{3}{2},-\dfrac{1}{3}}}$

Step-by-step explanation:

To find the roots, we must factorise the given quadratic equation.

$6 {x}^{2} - 7x - 3 = 0 \\ \\ = > 6 {x}^{2} - 9x + 2x - 3 = 0 \\ \\ = > 3x(2x - 3) + 1(2x - 3) = 0 \\ \\ = > (2x - 3)(3x + 1) = 0 \\ \\ = > 2x - 3 = 0 \: \: or \: \: 3x + 1 = 0 \\ \\ = > 2x = 3 \: \: or \: \: 3x = - 1 \\ \\ = > x = \frac{3}{2} \: \: or \: \:x = \frac{ - 1}{3}$

Hence, the roots are 3/2 and -1/3.

Answer 2

Answer:

3/2 and -1/3 are the answers