find the zeroes of polynomial f(x)=x^2+√2x-4
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Answer:
The answer is (x-√2)(x+2√2)
Step-by-step explanation:
We have the quadratic equation x^2+√2x-4=0
=> x^2 + 2√2x - √2x - 4 = 0
=> x(x+2√2) -√2(x+2√2) = 0
=> (x-√2)(x+2√2)=0
Hope you understood the answer
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