Question

find the zeroes of polynomial p(t)=t^3-4t​

Answer 1

Answer:

t = 0, 2, -2

Step-by-step explanation:

Given

p(t) = t^3 - 4t

for zeroes of polynomial p(t) = 0

${t}^{3} - 4t = 0$

$t( {t}^{2} - 4) = 0$

$t = 0$

${t}^{2} - 4 = 0$

${t}^{2} + 2t - 2t - 4 = 0$

$t(t + 2) - 2(t + 2) = 0$

$(t - 2)(t + 2) = 0$

$t = 2$

$t = - 2$

Hope it Helps

Answer 2

Answer:

$0,2,-2$

Step-by-step explanation:

It is the correct answer.