Question

Find the zeroes of polynomial p(x)=x2-9.

Answer 1

p(x) = x²-9

p(x) = x² - 3²

p(x) = (x-3)(x+3)

(x-3)(x+3) = 0

x-3 = 0

x = 3

and

x+3 = 0

x = -3

Therefore,the zeroes of the given polynomial are 3 and -3.

Hope it helps.....

Answer 2

Hey there !!

P(x)=x²-9
       =x²-3²

     =(x+3)(x-3)

(x+3)(x-3)=0

x+3=0          x-3=0

x=-3           x=3

So x=3,-3 are zeroes of P(x)=x²-9.