Question

s-t=3 & s/3+t/2=6 solve it using elimination method

Answer 1

S-t=3 (1)
S/3+t/2=6 (2)

Multiplying (2) by 2
Therefore
2s/3+t=12
Adding 1 and 2
(S-t)+(2s/3 +t)= 15
= 5s/3=15
= s =9
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Answer 2

Given:

s - t=3

$\frac {s}{3} + \frac {t}{2} = 6$

To find:

The value of s and t

Answer:

Given equations are

s - t = 3

s = 3+t ------ (1)

$\frac {s}{3} + \frac {t}{2}=6$

$\frac {2s+3t} {6}=6$

2s + 3t = 36 ----- (2)

Substitute equation (1) in (2)

2(3+t) + 3t=36

6 + 2t + 3t=36

5t + 6=36

5t = 36-6

5t = 30

$t =\frac {30} {5}=6$

t=6

Substitute the t value in equation (1)

s = 3+6

s = 9

The values are t=6 and s=9