Question

Find the zeroes of polynomial x2-3 and verify the relationship between the zeroes and the
coefficients.
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Answer 1

Answer:

P(x)=x2−3

x2−3=0

(x)2−(3–√)2

(x−3–√)(x+3–√)=0

x=3–√,−3–√

α=3–√,β=−3–√

α+β=3–√−3–√=0

α⋅β=3–√(−3–√)=−3

ax2+bx+c=0

α+β=−ba=−01=0