Question

find the zeroes of polynomial x²-3x-10​

Answer 1

Answer:

x²-3x-10 = x²+2x-5x-10

=x(x+2)-5(x+2)

=(x+2)(x-5)

Step-by-step explanation:

hence the zeros are 5 ,-2

Answer 2

Step-by-step explanation:

x2-3x-10=0

x2-5x+2x-10=0

x(x-5)+2(x-5)=0

(x-5)(x+2)=0

if x-5=0

then x=5

and if x+2=0

then x=-2

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