Question

Find the zeroes of quadratic polynomial 2x 2-25

Answer 1

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Answer 2

Answer:

The value of x in the given polynomial is $\pm \frac { 5 } { \sqrt { 2 } }$

Solution:

Given,

The quadratic polynomial is  

$2x^2-25$

Let

$2x^2-25= 0$

To factorize this term,

$2x^2-5^2= 0$

We know that,

$(a^2-b^2)= (a+b)(a-b)$

Then the terms will be,

$\begin{array} { c } { ( \sqrt { 2 } x ) ^ { 2 } - 5 ^ { 2 } = 0 } \\\\ { ( \sqrt { 2 } x + 5 ) ( \sqrt { 2 } x - 5 ) = 0 } \\\\ { x = - \frac { 5 } { \sqrt { 2 } } } \\\\ { x = + \frac { 5 } { \sqrt { 2 } } } \end{array}$

Then, the value of x is

$\pm \frac { 5 } { \sqrt { 2 } }$