Question

Find the zeroes of quadratic polynomial 4x square-7

Answer 1

Step-by-step explanation:

4x^2-7=0

x^2=7/4

x=+-√7/4

x=√7/4,x=-√7/4

hope it will help u

Answer 2

$x {}^{2} = 7 \div 4 \\ x = \sqrt{7 \div 4} \\ x = + \sqrt{7} \div 2 \: \: and \: - \sqrt{7} \div 2$

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