Question

find the zeroes of quadratic polynomial f(x)= x*2 3x-28 and verify that relationship between the coefficient of polynomial​

Answer 1

Step-by-step explanation:

) = x² - 3x - 28

To find zero

put f(x) = 0

x² - 3x - 28 = 0

x² - 7x + 4x - 28 = 0

x ( x - 7 ) + 4 (x - 7 ) = 0

( x - 7 )( x + 4 ) = 0

x = 7 & -4

let α = 7 and β = -4

Now to verify the relation

sum of zeroes = α + β = 7 + (-4) = 3

\frac{-coefficient\:of\:x}{Coefficient\:of\:x^2}=\frac{-(-3)}{1}=3

Coefficientofx

2

−coefficientofx

=

1

−(−3)