Question

find the zeroes of quadratic polynomial x²+7x+10 and verify the relationship between the zeroes and the co-efficients​

Answer 1

Answer:

Step-by-step explanation:

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

Hope it helps

Answer 2

HEY MATE!

_________________☆

HERE IS YOUR ANSWER:

In equation x^2+7x+10=0

x^2+5x+2x+10=0

x(x+5)+2(x+5)=0

(x+2)(x+5)=0

x+2=0 and x+5 =0

x=-2 and x=-5

VERIFICATION :

Sum of zeroes =-b/a=-7/1=-2+(-5)=-2-5=-7

Product of zeroes=c/a=10/1=(-2)(-5)=10

HOPE IT HELPED ^_^