Question

find the zeroes of quadratic polynomial10x square-7x-12 and verify realtionship between the zeroes and coefficient​

Answer 1

Answer:

zeros are (- 4/5) and 1.5

Step-by-step explanation:

ax² + bx + c = 0

$x_{12}$ = (- b ± √D) ÷ 2a

D = b² - 4ac

$x_{1}$ + $x_{2}$  = - $\frac{b}{a}$

$x_{1}$ × $x_{2}$ = $\frac{c}{a}$

~~~~~~~~~~~~  

10x² - 7x - 12 = 0

D = (- 7)² - 4×10×(-12) = 529

$x_{12}$ = (7 ± 23) / 20

$x_{1}$ = 3/2 = 1.5

$x_{2}$ = - 16/20 = - 4/5

1.5 + (- 4/5) = - (- 7/10)

1.5 × (-4/5) = - 12/10