Math, asked by 016, 8 months ago

find the zeroes of
${8x}^{2} - 4$
...
full solution required...

Answers

Answered by ammu540

0

Answer:

0,2root2

Step-by-step explanation:

8x²-4/0

(2root2x-2)(2root2+2)=0x=0,2root2

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