Math, asked by vidhenpatel, 9 months ago

Find the zeroes of
 \sqrt{2} x^{2}  + 7x + 5 \sqrt{2}

Answers

Answered by muskan610
1

Step-by-step explanation:

 \sqrt{ {2x}^{2} }  + 2x + 5x + 5 \sqrt{2}

 \sqrt{2} x(x +  \sqrt{2} ) + 5(x +  \sqrt{2} )

(x +  \sqrt{2} )( \sqrt{2} x + 5)

x =  -  \sqrt{2}  \: and \:  \frac{ - 5}{ \sqrt{2} }

Answered by tahseen619
1

Answer:

 -  \sqrt{2}   \:  \:  \: \: and \:  \:  \:  \:  \:  \:  \:   - \frac{5}{ \sqrt{2} }  \\

Step-by-step explanation:

see in the attachment.

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