Math, asked by Sahil1231, 1 year ago

find the zeroes of
$x {}^{2} + 6x + 5$

Answers

Answered by Anonymous

2

x^2 + 6x + 5 = 0

x^2 + 5x + 1x + 5 =0

x (x + 5) + 1 (x + 5) = 0

(x+1)(x+5) = 0

x =-1 , x = -5

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