Math, asked by gopivythees, 8 months ago

Find the zeroes of the following
quaderatio polynomial and verify the
relationship blw the zeroes & the
coefficients .4x^2-3x-1​

Answers

Answered by FantasticQueen
2

\huge\underline\mathfrak{SolUtiOnS}

    \huge\implies \large\sf \:4 {x}^{2}  - 3x - 1 \\  \\  \huge \implies \large \sf { x}^{2}  - 4x + x - 1 \\  \\  \huge \implies \large \sf \: 4x(x - 1) + 1(x - 1) \\ \\   \huge \implies \large \sf (4x + 1)(x - 1) \\

\huge\bold\implies\huge\boxed{X =\frac{-1}{4}\; X=\:1 }

\huge\underline\mathrm\red{verifying\: the\: relationship}

   \implies  \large \tt \alpha  +  \beta  =   \frac{ - b}{a}  \\  \implies \large \tt  \frac{ - 1}{4}  + 1 =  \frac{3}{4}  \\

  \implies\large \tt  \alpha  \times  \beta  =   \frac{c}{a}  \\  \implies \:  \large \tt \frac{ - 1}{4}  \times 1 =  \frac{ - 1}{4}

\huge{\underline{\tt{Hence\; verified}}}

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