Question

find the zeroes of the following quadratic polynomial and vrrify the relationship between the zeroes and the coefficient x²-x-72
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Answer 1

Answer:

9 & – 8.

Step-by-step explanation:

x²-x-72

x²-9x+8x-72

x(x–9) + 8(x–9)

(x–9)(x+8)

x=9, x= –8

VERIFICATION::--

SUM OF ZEROES = – b/a

9+(-8)= - (-1)/1

1 = 1

PRODUCT OF ZEROES = c/a

9*(-8) = -72/1

-72 = -72

I HOPE IT HELPS U

Answer 2

${\huge{\red{\mathcal{ANSWER :}}}}$

x² - x - 72 = x² - 9x + 8x - 72 = 0

= (x² - 9x) + (8x - 72) = 0

= x( x - 9) + 8(x - 9) = 0

= ( x - 9) ( x + 8) = 0

Thus, (x - 9) = 0 or (x + 8) = 0

So, x = 9 and x = (-8).

Let, the zeroes of the given quadratic polynomial be 9 and (-8).

So,

$\longrightarrow$ Sum of zeroes = 9 + (-8)

= 9 - 8

= 1

= -(Coefficient of x)/Coefficient of x²

$\longrightarrow$ Product of zeroes = 9 × (-8)

= -72

= Constant term/Coefficient of x²