Question

Find the zeroes of the following quadratic
polynomials and verify the relationship between
the zeroes and the coefficients :

x2-16​

Answer 1

Answer:

Zeroes will be +4 and -4

Step-by-step explanation:

Here,to find zeroes

${x}^{2} - 16 = 0 \\ {x}^{2} - {4}^{2} = 0 \\ (x - 4)(x + 4) = 0 \\ x = 4 \\ x = - 4$

Also, sum of zeroes= 0 , -b/a= 0

and product of zeroes= -16 =c/a

Hence proved.