if a three-digit number is selected at random from the integers 100 to 999, inclusive, what is the probability that the first digit and the last digit of the integer will both be exactly two less than the middle digit?
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Step-by-step explanation:
You are asked about all 3 digit numbers that conform to the follow type: ABA , where A= B-2.
There are 900 numbers between 100 and 999 (inclusive).
7:900
Numbers of the form ABA are: 131, 242,353,464,575,686,797 = total 7
Thus the probability asked = 7/900
B is the correct answer.
Hope this helps.
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