Question

find the zeroes of the following quadratic Polynomials and verify the relationship between the zeroes and the coefficient (1) x^2 -2x -8​

Answer 1

Answer:

x=(-2); x=4

Step-by-step explanation:

$x^{2}-2x-8$

$x^2-4x+2x-8$

$x(x-4)+2(x-4)$

$(x+2)(x-4)$

$x=(-2); x=4$

$\alpha = -2; \beta =4$

Now we know,

the equation is in the form of $ax^2+bx+c$

Verification of relationship:

1)Sum of zeroes: $\alpha + \beta = -b/a$

                          $-2+4=2/1$

                             $2=2$

2)Product of Zeroes: $\alpha * \beta = c/a$

                                  $-2*4=-8/1$

                                  $-8=-8$