find the zeroes of the p(x) =(x-3) (x+2)
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Answered by
0
The zeros are
x=3. x=-2
x=3. x=-2
Answered by
4
Hi ,
It is given that ,
P( x ) = ( x - 3 )(x + 2 )
To find zeroes of P( x ) , we have
to take P( x ) = 0
( x - 3 )( x + 2 ) = 0
x - 3 = 0 or x + 2 = 0
x = 3 or x = - 2 ,
Therefore
- 2 , 3 are zeroes of P( x ) .
I hope this helps you.
: )
It is given that ,
P( x ) = ( x - 3 )(x + 2 )
To find zeroes of P( x ) , we have
to take P( x ) = 0
( x - 3 )( x + 2 ) = 0
x - 3 = 0 or x + 2 = 0
x = 3 or x = - 2 ,
Therefore
- 2 , 3 are zeroes of P( x ) .
I hope this helps you.
: )
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